-22x^2+29x-9=0

Solution for -22x^2+29x-9=0 equation:

-22x^2+29x-9=0

a = -22; b = 29; c = -9;
Δ = b2-4ac
Δ = 292-4·(-22)·(-9)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-7}{2*-22}=\frac{-36}{-44}
=9/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+7}{2*-22}=\frac{-22}{-44}
=1/2
$